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Anonymous 09/04/14(Thu)21:41 UTC+1 No.6735576 Report

>If c^2=a^2+b^2 and a is greater than zero, then solve for a in terms of b and c.

why am i struggling...
>>
Anonymous 09/04/14(Thu)21:42 UTC+1 No.6735577 Report

>>6735576
a^2 = c^2 - b^2
a = (c^2 - b^2)^0.5

Now leave
>>
Anonymous 09/04/14(Thu)21:44 UTC+1 No.6735578 Report

>>6735577
so the
<a is greater than zero, then solve for a in terms of b and c.
is just there to make you feel stupid? they could of just said solve for a...
>>
Anonymous 09/04/14(Thu)21:46 UTC+1 No.6735582 Report

>>6735578
Look at the ^0.5 part again. That's a square root. Please tell me the square root of any number equal to or less than zero that doesn't involve complex numbers.
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