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Anonymous 09/04/14(Thu)23:16 UTC+1 No.6735782 Report

The answer to b is suppose to be -1/4. What should I do to get there?
>>
Anonymous 09/04/14(Thu)23:19 UTC+1 No.6735788 Report

Multiply by 2x/2x
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Anonymous 09/05/14(Fri)00:07 UTC+1 No.6735855 Report

In the denominator, you used 2 for f(2), but in the numerator you used 1/2 for f(2). Fix that and try what the other anon said, and let us know if that doesn't work either.
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Anonymous 09/05/14(Fri)00:09 UTC+1 No.6735861 Report

>>6735788
It works, but for what reason did you choose 2x/2x specifically?
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Anonymous 09/05/14(Fri)00:11 UTC+1 No.6735867 Report

>>6735861
Not that anon, but multiplying by 2x/2x is the same as multiplying by one. More than that, it also gets the denominators in the top part of the fraction to be the same, so then you can do more stuff with it.
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Anonymous 09/05/14(Fri)00:25 UTC+1 No.6735891 Report

>>6735788
>>6735855
>>6735867
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Anonymous 09/05/14(Fri)00:31 UTC+1 No.6735902 Report

>>6735782
Here's what I did.
Find a common denominator for the top part of the fraction. You'll quickly see that things can cancel out, provided you pulled out a -1 from one of them. Try it.
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Anonymous 09/05/14(Fri)06:35 UTC+1 No.6736546 Report

>>6735782
ITT: Retards

OP, do you even L'Hopital's rule? It's indeterminate form. Take the derivative of numerator and denominator.

Although, I think you made a mistake in formulating the question because according to what you wrote f(2) equals both 1/2 and 2 at the same time. This is not a function...
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Anonymous 09/05/14(Fri)06:41 UTC+1 No.6736555 Report

>>6735891
That evaluates to 0, not -1/4. The way you wrote it before evaluates to -1/4
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noko 09/06/14(Sat)06:19 UTC+1 No.6738221 Report

First step is to find common denominator for the numerator and combine the terms. Then multiply by -1/-1 so shit cancels.

1/x-1/2 = (2-x)/2x = (x-2)/-2x

(x-2)/-2x * 1/(x-2) = 1/-2x

x=2, 1/-2x = -1/4
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